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Muon Decay Special Relativity Proof Debunked

Author:

Kassir, Radwan M.

Category:

Research Papers

Sub-Category:

Relativity Theory

Language:

English

Date Published:

February 10, 2021

File:

/Research Papers-Relativity Theory/Download/8693

Downloads:

579

Keywords:

Muon, Special Relativity, Time Dilation

Abstract:

The cosmic ray muon decay in the upper atmosphere is claimed by relativists to be an evidence of the relativistic time dilation. They consider it as a reliable experimental proof of the special relativity. This paper reveals the unviability of this claim, using an analytical approach. The time and space intervals between the events of the muons formation and their arrival to the Earth surface are analyzed by the means of the Lorentz transformation. Contradictory findings are obtained.

Comments

J. Zwarts(Netherlands):

What is put in the comment field and looks good in there does obviously not anymore after being posted.
Again in simple text form:

By using the LT you must also consider the transformation of the time coordinates:
Dt'= gam(Dt-Dx.v/c2) ; where D means delta.
In your (i) it gives : Dt'= gam(Dt-Dxu.v/c2) and
in your (ii) it gives : Dt'= gam(Dt-DxE.v/c2)
From this follows that both Dt' are not zero.
This means that your result is not a length observation.
For a proper length observation from K', you need to have Dt'=0, observation at one moment in time.
Like this, using the inverse LT: L= x1u-x1E = gam(x1u'-x1E') + gam.v(t1u'-t1E') and
with t1u'-t1E'= 0 we get L=gam.L' and L'= L/gam.

Note that : Dt= t1u-t1E= gam(t1u'-t1E'+v(x1u'-x1E')/c^2) = gam.v.L'/c^2 is not zero.

Posted: February 26, 2021 @ 6:43:36 am

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George Storm:

Apologies for downvote - accidental click.
i tried to reverse it, but couldn't find a mechanixm

Posted: March 24, 2021 @ 10:44:56 am

J. Zwarts(Netherlands):

By using the LT you must also consider the transformation of the time coordinates:
∆t′=????(∆t−∆x.????/c2)
In your (i) it gives : ∆t′= ????(∆t−∆????????.????/c2) and
in your (ii) it gives : ∆t′= ????(∆t−∆????E.????/c2)
From this follows that ∆???????? = ∆????E and with your input that L=0.
The conclusion is that your analysis is incorrect.

Posted: February 15, 2021 @ 5:28:16 am

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